If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
Y^10 = 0
(X^26)/(Y^10) = 0
Y^10 = 0
Y^10 = 0
Y^10 = 0
x należy do R
(X^26)/(Y^10) = 0
(X^26)/(Y^10) = 0
X^26*Y^-10 = 0
x należy do R
x belongs to the empty set
(((X^26)/(Y^10))^-1)/2 = 0
x belongs to the empty set
| Ln(3x-19)=8 | | 3/4*3.14*512 | | 6x-18=5x-16 | | 3a+9=15 | | 9x^2+40x=25 | | 18-9w= | | 4z/-12=8 | | e(x-2)=7 | | 9[9-(-8x-9)]=648x+810 | | 10x^2+84x+185=0 | | -ax=b-c | | -y+42-3y=6 | | (2p-1)(p+3)-(7p+4)(p+3)= | | 1/3-4=-y | | 3=3(2x-4)-3(4x+4)-10 | | 36r^2-121= | | ln(6)+ln(x)=ln(6x) | | 42a^2+a-30=0 | | 6a^2-28a+16= | | 28/5 | | 36=b(5)(6) | | (B/9)-.5=(5/18) | | (x)(-3)-4=-10 | | 81x+36x+20=0 | | (3x^-5/8y^-7)^-2 | | 0=20t-5(t^2)+25 | | 4x-3/8 | | 6x-2x+7=x-2+9 | | 5x+6=30+x | | 30xm+15xn-20ym-10yn= | | 25x^4-81y^2=0 | | 1/4x=x-33 |